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2 years ago

What is the slope of the line graphed in the coordinate grid?

Mathematics

1 answer:

zvonat [6]2 years ago

5 0

Answer:

3/4

Step-by-step explanation:

I drew a slope triangle and found the slope by finding the distance between two points on the line.

$vertical distance/horizontal distance$

Hope this helped!

You might be interested in

A rectangular room is 1.5 times as long as it is wide, and its perimeter is30 meters. find the dimension of the room.

Tpy6a [65]

Answer:

6 meters by 9 meters

Step-by-step explanation:

Step 1: Formula for perimeter of rectangle

Rectangle's perimeter = 2 (length) + 2 (width)

Rectangle's perimeter = 2 (length + width)

Step 2: Find the length and width in terms of x

Width = x

Length = 1.5 times width

Length = 1.5x

Step 3: Find x

Perimeter = 2(length + width)

30 = 2 (1.5x + x)

30/2 = 2.5x

15/2.5 = x

x = 6

Step 4: Find the length and width

Width = x = 6 meters

Length = 1.5x = 1.5(6) = 9 meters

Therefore, the dimensions of the room are 6 meters and 9 meters.

6 0

2 years ago

the population in a town is 10,000. The population is growing at a rate of 0.08. what will the population be in 10 years

cestrela7 [59]

Hope this helps have a nice day!!!!

7 0

2 years ago

a toothpaste shop 500 tubes were sold in August and managers hoping to boost sales 20% in September how many toothpaste tubes mo

Alexus [3.1K]

500×.20=100
500+100=600
600 toothpaste tubes

6 0

2 years ago

Please help me out I need it done ASAP

Anni [7]

Your answer will be letter b

3 0

2 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

1 year ago