Using the domain, it is found that x = -8 is excluded for the product.
The domain of a function is the <u>set that contains all possible input values</u>.
- In a fraction, the <u>denominator cannot be 0</u>.
In this problem, there are two fractions, and the points outside the domain, that is, the roots of the denominators, are excluded.
For the first fraction, they are:
Hence, x = -2(not an option) is excluded.
- x = 0 can be factored with the numerator of the second fraction, so not excluded.
For the second fraction, the roots of the denominator are:
Which is a quadratic equation with <u>coefficients</u> , hence:
x = -3 can be factored with the numerator of the first fraction, so only x = -8 is excluded.
A similar problem is given at brainly.com/question/13136492
Answer:
The answer is (2, 4.58)
Step-by-step explanation:
Let U = {all integers}.
Consider the following sets:
A = {x | x ∈ U and x > 3}
B = {x | x ∈ U and x is an even integer}
C = {x | x ∈ U and 2x is an odd integer}
D = {x | x ∈ U and x is an odd integer}
<span>
Use the defined sets to answer the questions.
Assuming 0 is an even integer, which set is the complement to set B?
<span>
D
</span> Which set is an empty set?
<span>
C</span>
Which set would contain the subset E = {1, 3, 5, 7}?
<span><span>
D</span></span></span>
I spent a lil time on it but I’ll let you know in a lil but if I have the answer:)