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3 years ago

Write an equation for each line that contains the given pair of points. (-6,1) (2,3)

Mathematics

1 answer:

Travka [436]3 years ago

4 0

Answer:

y = .25x + 2.5

Step-by-step explanation:

First find the slope which is m in y = mx + b. y = mx + b is the standard form for a line.

m = (y₂-y₁)/(x₂-x₁)

m = (3-1)/(2+6)

m = 2/8

m = 1/4

Plug that in.

y = 1/4x + b

To find b plug in one of the two points and solve.

3 = 1/4(2) + b

3 = 1/2 + b

3 - 1/2 = 1/2 - 1/2 + b

2.5 = b

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Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0

guajiro [1.7K]

Answer:

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

$\displaystyle -3x^4+27x^2+1200=0$

If we call $y=x^2$ , our equation becomes a second-degree equation

$\displaystyle -3y^2+27y+1200=0$

Dividing by -3

$\displaystyle y^2-9y-400=0$

Factoring

$\displaystyle (y-25)(y+16)=0$

It leads to these solutions

$\displaystyle y=25\ ,\ y=-16$

Taking back the change of variable, we have for the first solution

$\displaystyle x^2=25\Rightarrow x=-5,x=5$

Now for the second solution, we get imaginary (complex) values

$\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i$

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$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

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3 years ago

PLEASE HELP!!!!!Find the equation of each line and then put each equation into the form Ax+By=C where A,B, and C are integers

shutvik [7]

Answer:

y-5x-7=0

Step-by-step explanation:

m = -2-3/1-2

m=5

y-y1 = m(x-x1)

y-2=5(x+3)

y-2=5x +5

y-5x-7=0

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3 years ago