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inessss [21]
3 years ago
11

Write an equation for each line that contains the given pair of points. (-6,1) (2,3)

Mathematics
1 answer:
Travka [436]3 years ago
4 0

Answer:

y = .25x + 2.5

Step-by-step explanation:

First find the slope which is m in y = mx + b. y = mx + b is the standard form for a line.

m = (y₂-y₁)/(x₂-x₁)

m = (3-1)/(2+6)

m = 2/8

m = 1/4

Plug that in.

y = 1/4x + b

To find b plug in one of the two points and solve.

3 = 1/4(2) + b

3 = 1/2 + b

3 - 1/2 = 1/2 - 1/2 + b

2.5 = b

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Solve for x x squared plus 4X minus 21 equals 0
suter [353]

Answer:

x = -7 and x = 3

Step-by-step explanation:

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Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
guajiro [1.7K]

Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

5 0
3 years ago
PLEASE HELP!!!!!Find the equation of each line and then put each equation into the form Ax+By=C where A,B, and C are integers
shutvik [7]

Answer:

y-5x-7=0

Step-by-step explanation:

m = -2-3/1-2

m=5

y-y1 = m(x-x1)

y-2=5(x+3)

y-2=5x +5

y-5x-7=0

4 0
3 years ago
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