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Olin [163]
3 years ago
10

Please help me i would really appreciate it.

Mathematics
2 answers:
kaheart [24]3 years ago
6 0

Answer:

Question 11- 6.28 yards square

AnnyKZ [126]3 years ago
5 0

6.28 = Question 11

and i can not solve for 12 sorry

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Evaluate the line integral, where C is the given curve. (x + 4y) dx + x2 dy, C C consists of line segments from (0, 0) to (4, 1)
zubka84 [21]

Parameterize the line segments (call them C_1 and C_2, respectively, by

\vec r_1(t)=(1-t)(0,0)+t(4,1)=(4t,t)

\vec r_2(t)=(1-t)(4,1)+t(5,0)=(4+t,1-t)

both with 0\le t\le1. Then

\displaystyle\int_C(x+4y)\,\mathrm dx+x^2\,\mathrm dy

=\displaystyle\int_0^1\bigg((4t+4t)(4)+(4t)^2(1)\bigg)\,\mathrm dt+\int_0^1\bigg((4+t+4(1-t))(1)+(4+t)^2(-1)\bigg)\,\mathrm dt

=\displaystyle\int_0^115t^2+21t-8\,\mathrm dt=\boxed{\frac{15}2}

6 0
3 years ago
Find the zeros of the polynomial function f(x)= x(4x-3)(3x+2)<br> Please show work thank you
xz_007 [3.2K]

Answer:

x = -2/3, 0, 3/4

Step-by-step explanation:

The zeros of the polynomial are the solutions or roots or x-intercepts of the function. To find them, use the zero product property to solve for x. Use the property by setting each factor equal to 0.

x = 0                            4x-3=0                 3x+2 = 0

                                     x = 3/4                    x = -2/3

6 0
3 years ago
Read 2 more answers
Um help! how do I do this?
valkas [14]
1/2 t-4(2+t)=20
1/2 t-8-4t=20
least common multiple=2
t-16-8t=40
-7t=40+16
-7t=56
t=56/-7=-8

Answer: t=-8

To check
-8/2 - 4(2-8)=-4-4(-6)=-4+24=20
5 0
3 years ago
Read 2 more answers
Do not round intermediate calculations. round your answers to two decimal places. a. define a random variable number of times th
navik [9.2K]

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours

547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000

x = no. of times owner-occupied units had a water supply stoppage.

<h3>What is the probability at x =0?</h3>

P(x=0) = 547000/14770000

P(x=0) = 0.0370

Similarly, we have at x=1

P(x=1) = 5012000/14770000

P(x=1) = 0.3393

P(x=2) = 6110000/14770000

P(x=2) = 0.4137

P(x=3) = 2544000/14770000

P(x=3) = 0.1722

P(x=4) = 557000/14770000

P(x=4) = 0.0378

x           f(x)

0             0.0370

1              0.3393

2         0.4137

3              0.1722

4         0.0378

Total     1

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

To learn more about the probability distribution visit:

brainly.com/question/24756209

#SPJ1

7 0
2 years ago
Can you help me with my Math, please?
creativ13 [48]
The first poster is not an accurate representation of the painting, but the second poster is an accurate representation because the ratio between the first and original lengths did not equal the ratio between the first and original widths but the second poster's ratios were equal.
6 0
3 years ago
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