<span>2x+ y = 3
x = 2y - 1
Make sure there are NO SPACES in your answer. Include a comma in your answer.
It looks like I could substitute the x=2y-1. Into 2x+y=3
2(2y-1)+y=3
4y-2+y=3
5y=5
y=1
x=2(1)-1
x=1

(1,1)
CHECK
2x+y=3
2(1)+(1)=3
2+1=3
3=3
Left hand side=Right hand side
Check other equation
x=2y-1
1=2(1)-1
1=1
Therefore the solution is (1,1). Since the left hand side= right hand side in each equation</span>

8 0

3 years ago

(2x-7)^2 subtracted from 2

weqwewe [10]

Write out the expression 2 - (2x-7)^2. That's it.

But if you want to go further and remove the parentheses, first expand (2x-7)^2: (2x-7)^2 = 4x^2 - 28x + 49,

and then subtract this result from 2:

2 - (4x^2 - 28x + 49) (It's important to use parentheses here)

Now, following the distributive property of multiplication, remove the parentheses:

2 - 4x^2 + 28x - 49

Combining the constants, we get the final answer: - 4x^2 + 28x - 47

4 0

2 years ago