d=-5.5 should be the answer
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width.
Area = Length x Height
Area = (20 in) x (14 in)
Area = 280 in²
We are given that the area is only equal to 192 in². We subtract this value from the computed area.
Difference = 280 in² - 192 in²
difference = 88 in²
This area is equal to the area of the hollow space inside the frame. That is equal to,
height = 20 in - 2x
length = 14 in - 2x
The area,
88 = (20 - 2x)(14 - 2x)
Simplify the right hand side of the equation.
88 = 280 - 68x + 4x²
Divide the equation by 4,
22 = 70 - 17x + x²
Transposing,
x² - 17x - 48 = 0
The factors of the equation is 58.2.
Thus, the thickenss is equal to 58.2 in
Step-by-step explanation:
Area of a trapezoid is 1/2h(b1+b2)
Height is 8 in. Base 1 is 5 in and Base 2 is 10 in. Do not use the diagonal side.
For the triangle-scalene triangle area formula is bh/2 (base times height divided by 2) The base is 5 in and the height is 4 inches.
For the paralellogram multiply base by height. 6 multiplied by 5 is 30
Answer:
i don't understand
Step-by-step explanation:
Answer:
No.
Step-by-step explanation:
Well, is the points (1, -9) does satisfy the equation y = 3x - 6. Then, substituting the values of x, and, y, into the equation y = 3x - 6, we should get a true equation.
y = 3x - 6
-9 = 3 * 1 - 6
-9 = 3 - 6
-9 = -3.
So, the points (1, -9) does not satisfy the equation y = 3x - 6.
