In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=84°, and IJ = 2.9 feet. Find the length of JH to the nearest tenth of a foot.
2 answers:
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Answer:
<h2>Step-by-step explanation:
w = yh - 2yc³
First of all factorize y out of the expression on the right side of the equation
That's
w = y( h - 2c³)
Next divide both sides by (h - 2c³) to make y stand alone
We have
<h3>We have the final answer as
<h3>Hope this helps you