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Debora [2.8K]
3 years ago
13

Does anyone know the answer to this? I’m taking a quiz that I can’t afford to fail

Mathematics
1 answer:
love history [14]3 years ago
4 0

Answer:

D

Step-by-step explanation:

y=2sqrt(x-6)

   x-6=0

    +6   +6

{6,inf) U(0,inf)

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Is this correct?????
fomenos

Answer:  \bold{x^8}

<u>Step-by-step explanation:</u>

x^3\cdot x^5\quad =x^{3+5}\quad =\large\boxed{x^8}

7 0
3 years ago
Use the equation s = m - 7 to find the value of s when m = 10.
fgiga [73]
S=3
I believe
Because 7-10=3 and it don’t change the other way I think hahaha
7 0
3 years ago
Read 2 more answers
I’ll give brainlest I don’t know the answer:/ someone help bruh
cricket20 [7]

Answer:

(4,2)

Step-by-step explanation:

its where the point intersects which is (4,2)

6 0
3 years ago
Y varies directly with x and y=8 when x=-5
ale4655 [162]

Answer:

Y=K×X...... equation

When,Y=8 and X=-5

To find the constant (K)

we substitute for K in the equation

8=K×-5

8=-5K divide both sides by -5

8÷-5=-5K÷-5

K=-1.6

7 0
3 years ago
A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin
pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.  

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph.  Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, \text{ distance } =\text{ speed }\times \text{ time }

\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}

We are given that, time taken for both are same. So \frac{40}{a-11}=\frac{70}{a+11}

\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}

8 0
3 years ago
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