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alina1380 [7]
2 years ago
11

This negative when developed will produce a 4” by 6” photograph. What is the length of each negative, if the width is 24 millime

ters
Mathematics
1 answer:
Katarina [22]2 years ago
5 0
Anwer: 36 millimeters
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The Art Club at Reynolds High School (ROCA) is selling paintings and clay coffee mugs to raise money for a trip to all the museu
suter [353]

Answer:

See below and attached

Step-by-step explanation:

Let the number of paintings is x and the number of mugs is y.

<u>We have following inequalities:</u>

  • x + y ≤ 350
  • 20x + 15y > 4500

The graphical solution is attached.

<u>The solution is:</u>

  • 225 < x ≤ 350
  • 300 < y ≤ 350

6 0
2 years ago
The slope of EF¯¯¯¯¯ is −52.
9966 [12]

Based on the above, the segments that are perpendicular to EF are LM and NP.

<h3>Why is the segment are LM and NP perpendicular  to EF ?</h3>

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

Learn more about segments from

brainly.com/question/10565562

#SPJ1

5 0
2 years ago
Suppose 2/3 of people surveyed like the new trial flavor of chips. How many people would you have to select randomly, on average
mixas84 [53]

Answer:

To me it seems like 30

Step-by-step explanation:

5 0
3 years ago
A . it is increasing and linear
Paha777 [63]

Answer:

The answer is B.

Step-by-step explanation:

From the interval -6 < x < 0, the line is straight which is linear equation. The line shows its going down so it will be decreasing gradient.

8 0
2 years ago
A certain truck weighs 2 metric tons A person weighing 60 kg get in the truck followed by a 70 kg person how many kilograms does
DiKsa [7]
The truck now weighs 2130 kilograms. Hope this helps.
7 0
3 years ago
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