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ANTONII [103]
3 years ago
11

A rental car company charges $55.98 per day to rent a car and $0.14 for every

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

4 days

Step-by-step explanation:

0.14 × 375= $52.50

$300-52.50=247.50

247.50 ÷55.98= 4.42122186495

round 4.42122186495 to the nearest whole that won't go over 300 and its 4 at $223.92 and the if you add your 52.50 thats $276.42

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USPshnik [31]

Answer:

2/5cm or 0.4cm

Step-by-step explanation:

Area of square = Side^{2}

Thus, Side = \sqrt{Area}

= \sqrt{4/25}

= 2/5 cm = 0.4cm

4 0
3 years ago
CosA+cosB+cosC+cos(A+B+C)= cos(A+B).cos(B+C).cos(C+A)
RoseWind [281]

Answer:

cos (A+B+C)

Step-by-step explanation:

as A,B,C, are triangle we have A,B and C as 180

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3 years ago
Please please please!!!!! help!!!!
mrs_skeptik [129]

Answer:

32\588585+++==+++=+=4858i234[oy45873569756308

Step-by-step explanation:

8 0
3 years ago
A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, thi
pickupchik [31]
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5 0
4 years ago
Read 2 more answers
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
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