Answer:
corresponding angles postulate
Step-by-step explanation:
just took the test ;)
3k+10=2k-21
move 2k to the other side
sign changes from +2k to -2k
3k-2k+10=2k-2k-21( combine like terms)
3k-2k+10= -21
k+10=-21
move +10 to the other side
k+10-10= -21-10
k= -21-10
answer:
k= -31
Answer:
f=2/3
Step-by-step explanation:
Answer:
r= -sec(θ) x ∛2
θ=0
Step-by-step explanation:
Answer:
#5
x = 45
E
Step-by-step explanation:
Theorems you need:
- The measures of 2 adjacent angles that form a straight line with the outer sides add up to 180°.
- The sum of the interior angles of a triangle add up to 180° ((n-2)×180).
#5
Knowing those, you first want to find the triangle's 3 interior angles.
The angles <QSO & <QSR are adjacent (share a common ray) and form a straight line with the outer rays, therefore they add up to 180.
So m<QSO+m<QSR=180.
Rewrite the equation: m<QSR=180-m<QSO
Plug the known value in: m<QSR=180-(3x-17)
Distribution & Combining like terms: m<QSR=180-3x+17=197-3x
Now solve for the 3 interior angles to equal 180.
(197-3x)+(25)+(2x+3)=180
Combine like terms: 225-x=180
Isolate the x term (-225 to both sides): -x=180-225=-45
Isolate the x (×-1 to both sides):
x=45
