No, it is not a perfect cube. A perfect cube is a number that is obtained when you cube an integer. For example, 8 (cube of 2), 27 (cube of 3) and 64 (cube of 4). Since -3 cannot be obtained by cubing an integer, it is not a perfect cube.
Answer:r=3q+2/3
Step-by-step explanation:
Step 1: Flip the equation.
3r-6=9q-4
Step 2: Add 6 to both sides.
3r-6+6=9q-4+6
3r=9q+2
Step 3: Divide both sides by 3.
3r/3=9q+2/3
r=3q+2/3
Hopefully it’s right
