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tekilochka [14]
3 years ago
7

Give the function y=-5x+12, what is the output (y) when the input, x=-2?

Mathematics
1 answer:
artcher [175]3 years ago
6 0

Answer:

y=22

Step-by-step explanation:

y=-5(-2)+12

y=10+12

y=22

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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

3 0
3 years ago
. If m 4 = 105, then what is m 8?
polet [3.4K]
I believe the answer is 210 because 1m= 26.25 and that x's 8= 210


7 0
3 years ago
Read 2 more answers
Complete the table for y=1/2x-3
Readme [11.4K]

Tables are created by substitute a set of input values into the function to create outputs. The required table is as shown below

<em>x | y</em>

<em>0   -3 </em>

<em>1   -2.5</em>

<em>2   -2 </em>

<h3>Tables and values</h3>

Tables are created by substitute a set of input values into the function to create outputs

Using x = 0, 1 and 2 as the input values

Given the function

y = 1/2x - 3

If x = 0

y = 1/2(0) - 3

y = -3

If x = 1

y = 1/2(1) - 3

y = -2.5

If x = 2

y = 1/2(2) - 3

y = -2

Hence the required table is as shown below

x | y

0   -3

1   -2.5

2   -2

Learn more on tables and values here: brainly.com/question/12151322

#SPJ1

8 0
1 year ago
Please help me with this urgent
erma4kov [3.2K]
1 is b and it would be 164
5 0
2 years ago
How to expand (X+8) (X+3)
Wewaii [24]
(a+b)(c+d)=ac+ad+bc+bd\\\\(x+8)(x+3)=x\cdot x+3\cdot x+8\cdot x+8\cdot3\\\\=x^2+3x+8x+24=x^2+11x+24
6 0
3 years ago
Read 2 more answers
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