Log (rootx+1 + root x-1)

Mathematics

1 answer:

amid [387]2 years ago

7 0

Answer:

Step-by-step explanation:

dy/dx = d/dx log root under x-1 / root under x+1

dy/dx = root under x+1 / root under x-1 * 1/(x+1)^2/3 * 1/root under x-1

dy/dx = (x+1)^2/ x-1

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