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jasenka [17]
3 years ago
5

Log (rootx+1 + root x-1)

Mathematics
1 answer:
amid [387]3 years ago
7 0

Answer:

Step-by-step explanation:

dy/dx = d/dx log root under x-1 / root under x+1

dy/dx = root under x+1 / root under x-1 * 1/(x+1)^2/3 * 1/root under x-1

dy/dx = (x+1)^2/ x-1

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A person at the top of a lighthouse sights a boat in the water. The angle of depression is 50. If the lighthouse is 70 feet high
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58.7 feet (3 s.f.)

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Sam typed 100 words in 5 minutes. what is sam’s gwam?
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4 years ago
A researcher tests the braking distances of several cars. The braking distance from 60 miles per hour to a complete stop on dry
ZanzabumX [31]

Answer:

The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The braking distances of a sample of cars are normally distributed, with a mean of 129 feet and a standard deviation of 5.18 feet.

This means that \mu = 129, \sigma = 5.18

What is the longest braking distance one of these cars could have and still be in the bottom 1%?

This is the 1st percentile, which is X when Z has a pvalue of 0.01, so X when Z = -2.327.

Z = \frac{X - \mu}{\sigma}

-2.327 = \frac{X - 129}{5.18}

X - 129 = -2.327*5.18

X = 116.94

The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.

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3 years ago
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