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jasenka [17]
3 years ago
5

Log (rootx+1 + root x-1)

Mathematics
1 answer:
amid [387]3 years ago
7 0

Answer:

Step-by-step explanation:

dy/dx = d/dx log root under x-1 / root under x+1

dy/dx = root under x+1 / root under x-1 * 1/(x+1)^2/3 * 1/root under x-1

dy/dx = (x+1)^2/ x-1

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