we have

see the attached figure to better understand the problem
we know that
The perimeter of the triangle is equal to

and
the area of the triangle is equal to

in this problem

we know that
The distance between two points is equal to

Step 
<u>Find the distance AB</u>

Substitute the values in the formula



Step 
<u>Find the distance BC</u>

Substitute the values in the formula



Step 
<u>Find the distance AC</u>

Substitute the values in the formula



Step 
<u>Find the distance DC</u>

Substitute the values in the formula



Step 
<u>Find the perimeter of the triangle</u>

substitute the values


therefore
The perimeter of the triangle is equal to 
Step 
<u>Find the area of the triangle</u>

in this problem

substitute the values


therefore
the area of the triangle is 