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Alla [95]
4 years ago
6

What is the truth value for the following conditional statement? p: false q: true ∼q → ∼p

Mathematics
2 answers:
Leno4ka [110]4 years ago
7 0

Answer:

p false

Step-by-step explanation:

Artyom0805 [142]4 years ago
4 0

Answer:

Truth value of ~p → ~q will be False.

Step-by-step explanation:

If the truth value of conditional statement p is false then the truth value of

~p will be True

If the truth value of other statement q is True then the truth value of ~q will be False

We know truth value of the implication of two conditional statements a → b is False only when a is true and b is false.

Therefore, ~p → ~q will be False.

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Answer:

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Step-by-step explanation:

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Rolling a number greater than 3 means you can roll a 4, 5, or 6, which contains rolling a 6. So, the probability is (1+1+1)/6=3/6=\boxed{1/2}

b)

Rolling a number less than 5 means you can roll a 1, 2, 3, or 4, but because you could also roll an even number, so you could also roll a 6.

So, the probability is (1+1+1+1+1)/6=\boxed{5/6}

c)

Rolling a 4 or an odd number means you can roll a 1, 3, 5, or 4. So, the probability is (1+1+1+1)/6=4/6=\boxed{2/3}

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