63. it's a cube so all you have to do is find the surface area of one side and multiply it by 6 (or you can use the actual formula)
side length^2= 8^2=64
64*6=384cm^2
Answer:
= 12
Step-by-step explanation:
area of a rectangle = width x length
Given:
- area = 44 m²
- width = 3 2/3 m
- length =
m
Substitute given values:
area of a rectangle = width x length
⇒ 44 = 3 2/3 x ![x](https://tex.z-dn.net/?f=x)
⇒
= 44 ÷ 3 2/3
⇒
= 12
1) x² + 8x + 15 = 0
Now what multiples to 15 and adds to 8? 5 and 3, 5x3=15, 5+3=8
so its
(x+5)(x+3)=0
now solve
x+5=0 x+3 =0
x = -5 x = -3
so the solution is -5, -3
4) x² - 11x + 28 = 0
what multiples to 28 and adds to -11? -7 and -4
(x-7)(x-4) =0
x= 7, 4
10) x² = 17x - 72 (okay ill do 3 of them)
first get numbers on same side where x² is positive
x² -17x + 72 = 0
what multiples to 72 and adds to -17? -9 and -8
(x-9)(x-8)=0
x= 9, 8
Answer:
We need a sample of at least 82 female white-tailed deer
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.99}{2} = 0.005](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.99%7D%7B2%7D%20%3D%200.005)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.575](https://tex.z-dn.net/?f=z%20%3D%202.575)
Now, find the margin of error M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
What sample size would you need to in order to estimate the mean weight of all female white-tailed deer, with a 99% confidence level, to within 6 pounds of the actual weight?
We need a sample of size at least n.
n is found when
. So
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![6 = 2.575*\frac{21}{\sqrt{n}}](https://tex.z-dn.net/?f=6%20%3D%202.575%2A%5Cfrac%7B21%7D%7B%5Csqrt%7Bn%7D%7D)
![6\sqrt{n} = 21*2.575](https://tex.z-dn.net/?f=6%5Csqrt%7Bn%7D%20%3D%2021%2A2.575)
![\sqrt{n} = \frac{21*2.575}{6}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B21%2A2.575%7D%7B6%7D)
![(\sqrt{n})^{2} = (\frac{21*2.575}{6})^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%28%5Cfrac%7B21%2A2.575%7D%7B6%7D%29%5E%7B2%7D)
![n = 81.23](https://tex.z-dn.net/?f=n%20%3D%2081.23)
Rounding up
We need a sample of at least 82 female white-tailed deer