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2 years ago

What are the domain and range of f(x) =4^x-8

Mathematics

1 answer:

Nutka1998 [239]2 years ago

6 0

The domain in this equation is -7<x<infinty and the range is negative infinty<y<1.5

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Find the area<br><br> Pls help me<br> Show/explain how to solve ty

bixtya [17]

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Step-by-step explanation:

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2 years ago

Please help I’m stuck.

Alika [10]

Answer: bro Idk imma try to figure it out

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8 0

2 years ago

La suma de dos número impares consecutivos es 100 . hallar la suma de cifras del mayor<br> numero

gtnhenbr [62]

<h2><u>solución</u></h2>

deja que los números sean x, and x + 2

sabemos que su suma es igual a 100, entonces

x + x + 2 = 100

2x = 100 - 2

2x = 98

x = 98 ÷ 2

x = 49

por lo tanto, el primer número es 49

y el segundo número es x + 2 = 49 + 2 = 51 (también es el mayor entre los dos números)

entonces suma de dígitos de mayor número = 5 + 1 = 6

Respuesta correcta de la pregunta anterior = 6

5 0

2 years ago

Five times the sum of a number and 7 is 8

denis-greek [22]

Answer:

(x + 7) 5 = 8

Step-by-step explanation:

A number = x

Sum = addition

(x + 7)

Five times would be

(x + 7) 5

And if equivalent to 8 then…

(x + 7) 5 = 8

7 0

2 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

2 years ago