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Nimfa-mama [501]
3 years ago
9

2/3 as afraction with a denominator of 6

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

4/6

Step-by-step explanation:

3 x 2 = 6

2 x 2 = 4

2/3 = 4/6

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Use the table to write a proportion.
Tanya [424]

Answer:

22

Step-by-step explanation:

7 0
3 years ago
In a certain town, 22% of voters favor a given ballot measure. for groups of 21 voters, find the variance for the number who fav
Galina-37 [17]
<span>c. 4.6
       
21 X .22= 4.6
       
Calculating the variance requires finding the product of 21 and 22%. To make this easier we convert 22% into it's decimal form and construct the equation. To back check this answer we can use 10% of 21 voters which equals 2.1% then double that amount to reach 4.2%, knowing that we now have a close approximation of the variance we can eliminate answers a, b, and d, leaving c as the only logical choice.</span>
5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
solong [7]

Answer:

1. Number line 2

2. Number line 1

3. Number line 4

4. Number line 3

Step-by-step explanation:

1. x – 99 ≤ -104

Solving by adding +99 on both sides

x - 99 +99 ≤ -104 +99

x ≤ -5

Number line 2 represent x ≤ -5

2. x – 51 ≤ -43

Adding +51 on both sides

x -51 +51  ≤ -43 +51

x ≤ 8

Number line 1 represent x ≤ 8

3. 150 + x ≤ 144

Adding -150 on both sides

150 + x -150 ≤ 144 -150

x ≤ -6

Number line 4 represent x ≤ -6

4. 75 < 69 – x

Adding +x on both sides

75 + x < 69 -x +x

x < 69 -75

x < -6

Number line 3 represent x < -6

8 0
3 years ago
How do I do this cause I don’t get it
mars1129 [50]

for the 0 u put zero the for 5 u put 40 then for 10 u put 80 then for 15 u put 120 then for 20 u put 160

6 0
3 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
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