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Nimfa-mama [501]

3 years ago

9

2/3 as afraction with a denominator of 6

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

4/6

Step-by-step explanation:

3 x 2 = 6

2 x 2 = 4

2/3 = 4/6

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What numbers are less than 2.98

alina1380 [7]

Answer:

... anything less than 2.98??

Step-by-step explanation:

7 0

2 years ago

Find M<1 and M<3 in the kite

Shalnov [3]

The angle of measure 1 is equivocal to its adjacent angle, so M<1 = 39 degrees
Because the summation of all angles of a triangle need to be 180 degrees, we can find M<3. We have an angle of 39 degrees and a right angle which is 90 degrees.Therefore M<3 is equal to 51 degrees

3 0

3 years ago

Find the value of each variable

kkurt [141]

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Step-by-step explanation:

3 0

3 years ago

Simplify: 9^-3<br><br><br> Please help!

dalvyx [7]

Answer:

Fraction form: 1/729

Decimal form: 0.00137174...

Exponent form: 3^-6

7 0

3 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago