Answer:
i dont know im just doing this for the points
142.35 miles. Just multiply 189.80 by 3/4 (or .75).
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
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⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
It is 20%. Assume Josh is 100000 and Jeff is 125000
The formula is (Jeff- Josh)/Jeff * 100 = (25000)/100000 *100 = 20%
<span>The salesman has observed that many students are looking for cars that cost less than $5,000. If he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, the distribution of the mean and the median will be the same.
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