Answer:
Step-by-step explanation:
bc²-2a/b=6(3)²-2×12/6=54-4=50
Let's actually find the roots, using the quadratic formula:
<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2
The discriminant here is negative, so the roots x will be complex:
-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2
These are irrational roots; they cannot be expressed as the ratios of integers.</span>
Answer:
If one −5s−7(8s−1): -61s+7
If two −5s−7(8s−1): -112s+14
Step-by-step explanation:
-5s-7(8s-1)
Multiply -7 onto 8s and -1:
-5s-56s+7
add -5s and -56s:
-61s+7
−5s−7(8s−1)−5s−7(8s−1)
Multiply both -7 to 8s and -1
-5s-56s+7-5s-56s+7
add:
-112s+14
First order all the numbers least to greatest.<span>
$28, $28, $30, $31, $35, $36, $41, $43
Because there are two numbers in the middle (no, one middle number).
Add the two together, and divide by 2
31 + 35 = 66
66/2 = 33
</span><span>B.$33 is your answer
hope this helps</span>
