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JulijaS [17]
3 years ago
10

An experiment was conducted, and it was determined that plants that received more than two hours of sunlight per day grew larger

than plants that received less than two hours of sunlight per day. Which of the following best describes this situation?
A. Based on the data, this is an example of correlation and causation.
B. Based on the data, this is an example of correlation.
C. Based on the data, this is an example of causation.
D. Based on the data, this is not an example of causation or correlation.
Mathematics
2 answers:
Allushta [10]3 years ago
6 0
D. Based on the data, this is not an example of causation or correlation
natka813 [3]3 years ago
5 0

Answer:

A) Based on the data, this is an example of correlation and causation.

Step-by-step explanation:

The correlating item is the sunlight

The causation is the growth vs. non growth:  The sunlight caused growth.  The lack of sunlight caused the plants not to grow as fast.

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In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
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Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

j = \sqrt{99.45}

j = 9.97

∴

\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

=  Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ =  Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 }  \\ \\  = Sin \ L = 0.18466 \\ \\  L = Sin^{-1} (0.18466) \\ \\  L = 10.64 ^0

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