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Citrus2011 [14]
3 years ago
13

Which situation can be modelled by tossing a coin twice?

Mathematics
1 answer:
neonofarm [45]3 years ago
8 0

Answer:

I personally think it is b. because there are only two choices, true or false. The answers are for 4 questions so,

2/4 = 1/2

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If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B3%7D%7B4%7D" id="TexFormula1" title="\frac{x+3}{4}" alt="\frac{x+3}{4}
natulia [17]

Answer:

option (b) is correct

inverse of function  f(x)=\frac{x+3}{4} is 4x+3

Step-by-step explanation:

Given function f(x)=\frac{x+3}{4}

We have to find the inverse of given function.

Let f(x) = y then taking inverse both sides, we get

f^{-1}(y)=f^{-1}(f(x))\\\\\ f^{-1}(y)=x

Substitute , x  and f(x) in given equation, we get,

f(x)=\frac{x+3}{4} \Rightarrow \frac{(f^{-1}(y))+3}{4}

Now solve for (f^{-1}(y)) , we get,

(f^{-1}(y))+3=4y

(f^{-1}(y))=4y-3

Thus, inverse of function  f(x)=\frac{x+3}{4} is 4x+3

Thus, option (b) is correct.

8 0
3 years ago
Read 2 more answers
The graph shows thar video sales at Bart's are nost often.
FrozenT [24]

Answer:

The answer is b

Less than 300

3 0
3 years ago
I NEED HELP.... IM TIMED!!! PLS SHOW WORK!!! +10 POINTS
Savatey [412]

Answer:

x=-17

Step-by-step explanation:

4 0
3 years ago
What is the solution of startfraction 1 over c minus 3 endfraction minus startfraction 1 over c endfraction = startfraction 3 ov
Sonbull [250]

The solution of the given equation can be all real numbers, except c = 0 and c = 3.

Lets simplify the given problem,

1/c-3 - 1/c = 3/ (c-3)

As the denominators cannot be equal to zero (0) because a division by zero (0) is undefined.

Next, we would multiply both sides of the given by the lowest common multiple (LCM).

The lowest common multiple (LCM) is c(c - 3).

c-[c-3] = 3

c-c+3 = 3

0 = 3-3

0=0

Therefore, the solution of the given equation can be all real numbers, except c = 0 and c = 3.

Learn more about Fractions on:

brainly.com/question/368260

#SPJ4

4 0
2 years ago
See attachment for question (I will report you if you are only doing it for the points)
vovikov84 [41]

Answer:

x => y

-6 => 9

3 => 5

15 => -3

-12 => 15

Step-by-step explanation:

Given the domain function, {-12, -6, 3, 15}, and the equation of the function, y = -\frac{2}{3}x + 7, we can complete the given table by simply plugging in the value of either x to find y, or y to find x in the table given. The domain values are all x-values you have in the table.

Find y when x = -6:

y = -\frac{2}{3}(-6) + 7

y = -\frac{2}{1}(-2) + 7

y = 2 + 7

y = 9

Find x when y = 5:

5 = -\frac{2}{3}x + 7

5 - 7 = -\frac{2}{3}x + 7 - 7

-2 = -\frac{2}{3}x

-2 = \frac{-2x}{3}

-2*3 = \frac{-2x}{3}*3

-6 = -2x

\frac{-6}{-2} = \frac{-2x}{-2}

3 = x

x = 3

Find y when x = 15:

y = -\frac{2}{3}(15) + 7

y = -\frac{2}{1}(5) + 7

y = -10 + 7

y = -3

Find x when y = 15:

15 = -\frac{2}{3}x + 7

15 - 7 = -\frac{2}{3}x + 7 - 7

8 = -\frac{2}{3}x

8 = \frac{-2x}{3}

8*3 = \frac{-2x}{3}*3

24 = -2x

\frac{24}{-2} = \frac{-2x}{-2}

-12 = x

x = -12

7 0
3 years ago
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