<span>No entiendo esto, esta no es una pregunta. Más que un hecho realmente.</span>
Hello,
1) Conditions:
x+2>=0==>x>-2
x>=0
So x>=0
1/5 ln(x+2)^5 +1/2 [ln x -ln(x^2+3x+2)^2]
=ln(x+2)+ ln√x - ln(x+1)(x+2)
Answer:
if the x is for multiplication this is a false statement the true answer would be5/8 if the x is a variable then x would =11.304
Step-by-step explanation:
Answer:
D. Since the P-value is less than 0.05, we reject the null hypothesis and conclude that there is a difference in the softness level achieved by the two processes.
Step-by-step explanation:
H0: μ1 - μ2 = 0
Ha: μ1 - μ2 ≠ 0
Test statistic t = 3.328, P-value = 0.0014, DF = 69.97
The Critical value for df = 69.97 is t ( ∝/2) (df): ±1.9945
The calculated t value falls in the critical region so H0 is rejected
As P - value is less than significance level H0 is rejected .
It is a two tailed test and the P - value is0.0014 which is less than 0.05 the significance level.
This means the softness achieved by Process A is considered to be not equal to the softness achieved by the Process-B .
Only choice D is correct.
