9514 1404 393
Answer:
y -2 = -2/3(x +4)
Step-by-step explanation:
There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.
That form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
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The two marked points are (-4, 2) and (5, -4). All we need is the slope.
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)
m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3
Using the first point, the equation for the line can now be written as ...
y -2 = -2/3(x -(-4))
y -2 = -2/3(x +4)
I believe the answer is 2.7 but I'm not sure...
Answer:
The coordinates are (50, 103)
Step-by-step explanation:
The three hallways are AB, BC, CD.
The co-ordinate of D is (50, 75).
The school's flagpole is 28 meters right of the point D.
Hence the y-coordinate for the flagpole will be same as D, that is 75.
The x-coordinate will be (28 + 75) = 103.
The location of the school's flagpole will be represented by (50, 103)
Answer:
x= -6
Step-by-step explanation:
18=x+14+x+16
18=2x+30
-30 -30
-12=2x
divide 2
-6=x
-7√5
rewrite 20 as 2^2·5
factor 4 out of 20. negative ∛4(5)-√5
rewrite 4 and 2^2 negative ∛2^2·5-√5
pull terms out from under the radical
-3(2√5)√5
multiply 2 by -3
-6√5-√5
subtract √5 from -6√5
-7√5
the answer is -7√5