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OlgaM077 [116]
3 years ago
15

The conditional relative frequency table was generated using data that compares the number of boys and girls who pack their lunc

h or buy lunch from the cafeteria. 35 total girls and 50 total boys were surveyed. How many students bought their lunch from the cafeteria? Round to the nearest whole number.
Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

Its 36 students

Step-by-step explanation:

Kaylis [27]3 years ago
4 0
36 students............................................
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One side of a kite is 5 cm less than 2 times the length of another. If the perimeter is 14 cm, find the length of each side of t
Phoenix [80]
<h3>Answer:</h3>

D) 4 cm, 3 cm

<h3>Step-by-step explanation:</h3>

Let x represent the length of "another" side. Then "one side" can be represented by (2x -5 cm).

The perimeter of the kite is the sum of two sides of each length:

... P = 14 cm = 2(x) + 2(2x -5 cm)

Dividing by 2 and collecting terms, we have ...

... 7 cm = 3x -5 cm

... 12 cm = 3x

... 4 cm = x . . . . the length of "another" side

... 2(4 cm) -5 cm = 3 cm . . . . the length of "one side"

The two different side lengths are 4 cm and 3 cm.

7 0
3 years ago
An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
2 years ago
33 folders cost \$2.91$2.91dollar sign, 2, point, 91.
vlada-n [284]

Answer:

The answer is 646.02 tell me if you need an explaination

6 0
2 years ago
Simplify. (x3)5 5x3 x15 x2 x8
maks197457 [2]
You just combine like terms so it'll be 5x^43
3 0
3 years ago
Read 2 more answers
Grace is looking at a report of her monthly cell-phone usage for the last year to determine if she needs to upgrade her plan. Th
Alisiya [41]

Answer:

s ≈ 105

Step-by-step explanation:

<u>Given:</u>

  • The data set: 700, 735, 680, 890, 755, 740, 670, 785, 805, 1050, 820, 750

<u>To find:</u>

  • The standard deviation of the data

<u>Steps:</u>

To find the standard deviation, first write the computational formula for the standard deviation of the sample.

{s}= \sqrt{\frac{{\sum}{x^2} - \frac{({\sum}{x})^2}{n}}{n - 1}}

Take the square root of the answer found in step 7 above. This number is the standard deviation of the sample. It is symbolized by s . Here, we round the standard deviation to the nearest whole number.

{s} = \sqrt{10987.878787879} = 104.8231

Rounding to the nearest whole number:

s ≈ 105

6 0
1 year ago
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