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lilavasa [31]
3 years ago
8

What number would you add to both sides of x2 + 7x = 4 to complete the square? o 22

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

49/4

Step-by-step explanation:

x^2 + 7x = 4

Take the coefficient of x

7

Divide by 2

7/2

Square it

(7/2) ^2 = 49/4

Add this to each side

x^2 + 7x  +49/4= 4+49/4

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Can someone help me
kramer

i think its 13.3 correct m if im wrong

8 0
3 years ago
Plz help I will mark as the brainlist
tensa zangetsu [6.8K]

Answer:

1/25

Step-by-step explanation:

We can see that in this pattern, the denominator and the numerator of the next fraction cancel out; they're the same.

(1/2) x (2/3) x (3/4) = 1/4 (do you see it?)

The only things that do not cancel out are the numerator of the first fraction and the denominator of the last. So, in the end, the answer will be 1/25.

Hope this helps!

3 0
3 years ago
Who can answer this ??<br> Win BRAINLEST !<br><br> HELP <br> Thank You In Advance !
kirill [66]

ANSWER

( {x - 11)}^{2}  + ( {y - 5)}^{2}  = 16

EXPLANATION

The given circle has center:

(11,5)

and

radius: 4

The equation of a circle with center (h,k) and radius , r is given in standard form as;

( {x - h)}^{2}  + ( {y - k)}^{2}  =  {r}^{2}

We substitute the values into the formula to obtain,

( {x - 11)}^{2}  + ( {y - 5)}^{2}  =  {4}^{2}

( {x - 11)}^{2}  + ( {y - 5)}^{2}  = 16

5 0
3 years ago
Sum of n terms 1x2+2x3+3x4+4x5+...
lozanna [386]

Answer:

1/3(n+1)³

Step-by-step explanation:

1x2+2x3+3x4+4x5+...= 1²+1+2²+2+3²+3+...+n²+n+1=

=(1²+2²+3²+...+n²)+(1+2+3+...+n+1)=

=1/6n(n+1)(2n+1)+1/2(n+1)(1+n+1)=

=1/6(n+1)(n(2n+1)+3(n+2))=

=1/6(n+1)(2n²+4n+2)=

=1/6(n+1)*2(n+1)²=

=1/3(n+1)³

6 0
3 years ago
Can someone help me with this problem?
Mila [183]

Answer:

Answer is

Step-by-step explanation:

The answer 1 Its 35 Answer 2 14

8 0
4 years ago
Read 2 more answers
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