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2 years ago

A circle has a diameter of 26 units. What is the area of the circle to the nearest hundredth of a square unit.

Mathematics

1 answer:

iris [78.8K]2 years ago

7 0

9514 1404 393

Answer:

530.93 square units

Step-by-step explanation:

The area of a circle in terms of diameter can be found by ...

A = (π/4)d²

A = 3.14159/4×26² ≈ 530.929

Rounded to hundredths, the area of the circle is 530.93 square units.

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6. Find the area of the triangle below. Be sure to include the correct unit in your answer.

snow_tiger [21]

Answer:

512

Step-by-step explanation: area of triangle= 1/2*base*height

4 0

3 years ago

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After eating a meal at a restaurant, we decided to tip 25%, building a grand total of $87.50. What was the price before the tip?

CaHeK987 [17]

Answer:

65.62

Step-by-step explanation:

Given:

After eating a meal at a restaurant, we decided to tip 25%, building a grand total of $87.50.

To find:

Price before tip

Solution:

87.50 × 25% = 21.875

~Round~: 21.875 to 21.88

87.50 - 21 .88 = 65.62

Thus the price before the tip is 65.62

Check Answer:

Formula: Higher number - Lower number ÷ original number × 100

Solve:

87.50 - 65.62 = 21.88

21.88 ÷ 87.50=0.25005714285

0.25005714285 × 100 = 25.0057142857

Round - 25%

~lenvy~

3 0

1 year ago

In science class, Danny had 200ml of liquid. However, he spilt some of the liquid and now has 170ml left. What is the percent of

Bond [772]

Answer: 170

Step-by-step explanation: To find the percent change, simply multiply this number by 100.

8 0

2 years ago

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A blueberry recipe calls for 1\frac{3}{4} cups of sugar. How many cups of sugar would need to make the muffin recipe 3 times?

liraira [26]

Answer:

4 3/4

Step-by-step explanation:

Just multiply 1 3/4 and 3 = 4 3/4

4 0

2 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

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2 years ago