Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
Answer:
A≈78.54cm² Diamter= 10
Step-by-step explanation:
hope this helps
Answer:
Measure of angle 2 and angle 4 is 42°.
Step-by-step explanation:
From the figure attached,
m∠ABC = 42°
m(∠ABD) = 90°
m(∠ABD) = m(∠ABC) + m(∠DBC)
90° = 43° + m(∠DBC)
m(∠DBC) = 90 - 43 = 47°
Since ∠ABC ≅ ∠4 [Vertical angles]
m∠ABC = m∠4 = 42°
Since, m∠3 + m∠4 = 90° [Complimentary angles]
m∠3 + 42° = 90°
m∠3 = 90° - 42°
= 48°
Since, ∠5 ≅ ∠3 [Vertical angles]
m∠5 = m∠3 = 48°
m∠3 + m∠2 = 90° [given that m∠2 + m∠3 = 90°]
m∠2 + 48° = 90°
m∠2 = 90 - 48 = 42°
m∠3+ m∠4 = 90° [Since, ∠3 and ∠4 are the complimentary angles]
48° + m∠4 = 90°
m∠4 = 90 - 48 = 42°
Therefore, ∠2 and ∠4 measure 42°.
This is equivalent to:
(2.2533/2.59)(10^8/10^4)
(0.87)(10^4) which is:
0.87X10^4 which is equal to:
0.87X10000 which is equal to:
8.7X1000 and since 1000=10^3 we can say:
8.7X10^3
