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2 years ago

12

The data set shows the number of visitors to a museum every day for 10 days.

2 answers:

Lesechka [4]2 years ago

6 0

Answer: 202 and 219 are outliers

Step-by-step explanation:

this is true because all the other values are bigger.

kirill115 [55]2 years ago

5 0

D should be correct

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Which of the following has a shallower slope than the line 3x-1y=-1 ?

BaLLatris [955]

1/5 (c) since it goes up only one and then over 5

3 0

3 years ago

Read 2 more answers

Graph the function y=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-2-5" id="TexFormula1" title="\sqrt{x} -2-5" alt="\sqrt{

Rashid [163]

Answer:

(3, -4)

Step-by-step explanation:

The correct equation is:

$y=\sqrt{x-2}-5$

From the list of given points, we have to identify which point lies on the graph. This can be done by using the value of x-coordinates from the given points and see if they result in the corresponding y-coordinate:

For point (1, 4)

$y=\sqrt{1-2}-5=\sqrt{-1}-5$ , This is not equal to 4, so it does not lie on the graph of given function.

For point (3, -4)

$y=\sqrt{3-2}-5=\sqrt{1}-5=-4$ , The answer ans corresponding y-coordinate are the same. This means, (3, -4) point lies on the graph of given function.

Likewise, checking for 3rd and 4th point we find out that they do not lie on the graph.

So the correct answer is (3, -4)

5 0

2 years ago

Ray LN is the perpendicular bisector of segment JK.

scoray [572]

Answer:

ok i think "kp" is 17x but i am not 100% sure

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)

Triss [41]

$g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}$

The surface element is

$\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta$

and the integral is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta$

$=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)$

###

To compute the last integral, you can integrate by parts:

$u=r\implies\mathrm du=\mathrm dr$

$\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}$

$\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr$

For this integral, consider a substitution of

$r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds$

$\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds$

$\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds$

$=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds$

and the result above follows.

4 0

3 years ago

the expression y-x equals 0.7 if x and y have certain values. evaluate the following expressions with the same values of x and y

inessss [21]

Answer:

Step-by-step explanation:

y-x=0.7

y=x+0.7, so lets plug in that into the expressions instead of y

1)

(y-x)=

x+0.7-x=

x+0.7+(-x)=

x+(-x)+0.7=

x-x+0.7=

0.7

2)

(x-(x+0.7))/((x+0.7)-x)=

(x-x+0.7)/(x+0.7-x)=

(x-x+0.7)/(x+0.7+(-x))=

(x-x+0.7)/(x+0.7+(-x))=

(x-x+0.7)/(x+(-x)+0.7)=

(x-x+0.7)/(x-x+0.7)=

0.7/0.7=

1

6 0

2 years ago