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NISA [10]
3 years ago
12

The data set shows the number of visitors to a museum every day for 10 days.

Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Answer: 202 and 219 are outliers

Step-by-step explanation:

this is true because all the other values are bigger.

kirill115 [55]3 years ago
5 0
D should be correct
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Maria tests the effectiveness of an anti-depression drug by recruiting 500 participants and randomly assigning half e participan
Nady [450]

Answer:

D. The small p value and the small effect size suggest that the observed difference between the drug placebo groups are likely to be due to sampling error. This study should be replicated with a larger sample size.

Step-by-step explanation:

The p value is determined for any test before making a conclusion. If the p-value is smaller than critical value then we reject the null hypothesis which means that drug is not effective for the reducing depression. A very small p-value usually lesser than 0.05 indicates strong evidence against the null hypothesis.

6 0
3 years ago
What is the value of the expression (9+15)/3+2?
KIM [24]
(9+15)/3+2
24/3+2
8+2
10
6 0
3 years ago
Read 2 more answers
What is the value of x?
Orlov [11]

Answer:

x = 24.5

Step-by-step explanation:

There are two similar triangles. In similar triangles the sides are in proportion.

Let's name big triangle as triangle 1 and small triangle as triangle 2.

The sides of the big triangle:

27 as base and the longest side (x + 7)

The sides of the small triangle:

base = 27 - 6 = 21

longest side = x

We need to find the value of x using proportion.

27/21 = (x + 7)/ x

By cross multiplying, we get

27(x) = 21(x + 7)

27x = 21x + 147

27x - 21x = 147

6x = 147

Dividing both sides by 6, we get

x = 147/6

x = 24.5

The value of x = 24.5

Hope you will understand the concept.

Thank you.

5 0
3 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
3 years ago
Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39
m_a_m_a [10]

15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479

4 0
3 years ago
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