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horrorfan [7]
2 years ago
13

What causes the hidden node problem in a wireless local area network (wlan)?

Computers and Technology
1 answer:
VLD [36.1K]2 years ago
7 0

The causes is if a client (or node) can receive signals from an access point (AP), but there is hindrance that prevents the client from getting signals from the other clients that are linked to the network.

<h3>What is hidden node problem in wireless network?</h3>

The hidden node problem is known to often takes place if  two transmitting terminals side by side transmit data to a receiving terminal between them, and there is hinderance between the two sets of transmitted radio waves.

Note that The causes is if a client (or node) can receive signals from an access point (AP), but there is hindrance that prevents the client from getting signals from the other clients that are linked to the network.

Learn more about local area network from

brainly.com/question/8118353

#SPJ11

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All of the following are true of using the database approach to managing data except Group of answer choices Decentralized manag
kolezko [41]

Answer:

Decentralized management of data

Explanation:

  • The database management approach is one approach based on the improved standard file solution with the use of DBMS and allows for the stimulus access of data with a large number of users.
8 0
3 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
3 years ago
(25 POINTS) Some applications work on all devices while others work on some devices. True or False?
scoray [572]

Answer:

True.

Explanation:

It is true that some applications work on some devices but not on others. This is so because it depends on the operating system of each device, that is, if the device has an operating system compatible with the application in question, said application will work, but if, on the contrary, the operating system is not compatible, the application will not be useful in this.

7 0
3 years ago
To hide the ribbon, ______ on any one of the tabs of the ribbon.
Natasha_Volkova [10]
The ribbon is a set of toolbars at the top of the window in Office programs designed to help you quickly find the commands that you need to complete a task. Sometimes the ribbon can get hidden and it's hard to find. The quickest way to show the ribbon is to click on any visible tab, like Home<span>, </span>Insert<span> or </span>Design<span>. You might also want to hide the ribbon to maximize screen space.</span>
8 0
3 years ago
Which function would you use to make sure all names are prepared for a mailing label?
Akimi4 [234]

Start Word. ...

On the Mailings tab, in the Create group, click Labels.

Leave the Address box blank.

To select the label type and other options, click Options.

In the Label Options dialog box, make your choices, and then click OK.

4 0
3 years ago
Read 2 more answers
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