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Jobisdone [24]
3 years ago
15

11 Bob traveled 45 miles in 1.5 hours. The distance d and time I are in a proportional linear relationship Which graph represent

s this relationship?​

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

Graph (C)

Step-by-step explanation:

If Bob traveled 'y' miles in 'x' hours,

Distance traveled ∝ Time taken to cover the distance

y ∝ x

y = mx

Here, m = proportionality constant Or slope of the line

Since, Bob covered 45 miles in 1.5 hours,

m = \frac{45}{1.5}

m = 30 miles per hour

From the given graphs,

Graph (C) shows the slope = \frac{\text{Rise}}{\text{Run}}

                                             = \frac{60}{2}

                                             = 30 miles per hour

Therefore, Graph (C) will show the relationship.

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Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0
4 years ago
Round to the nearest tenth, I will give brainlyest PLEASE
BabaBlast [244]

1. cos B= a/x

x= 11/cos 37°

x= 13.77

2. tan A= a/x

x= 4/tan 41°

x= 4.60

3. sin B = x/c

x= sin 37° × 10.3

x= 6.20

4. tan A= a/b

tan A= 4/13

A= tan-1(0.31)

A= 17°6'10"

5. cos A= b/c

cos A= 12/13

A= cos -¹(0.92)

A= 22°37'12"

6. tan B= a/b

tan B= 3/3

tan B= 1

B= tan‐¹(1)

B= 45°

7 0
2 years ago
For the functions g and f simplify the following expressions. f(x) = 2x - 4
ira [324]

Answer:

Step-by-step explanation:

4 0
3 years ago
A northbound bus returns to the bus stop every 20 minutes. The southbound bus returns to the bus stop every 25 minutes.How long
Klio2033 [76]
They  stop at the  same time after 4  times for  the southbound bus to return and five times for the northbound bus returns to the bus stop
 
8 0
3 years ago
Read 2 more answers
Plz solve this ...fenz. .​
Kobotan [32]
Thats is the answer hope it helps

5 0
3 years ago
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