<span>17 1/3 + (-50 1/3) -5 1/2
= -33 - 5 1/2
= (</span>-33 ) + ( - 5 1/2)
<span>= -38 1/2
</span>
Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
13x-4
Step-by-step explanation:
MO=7x-4
NO=6x
MO+NO=?
7x-4+6x=13x-4
322.788 is the answer to your ?
