A rule of polygons is that the sum<span> of the </span>exterior angles<span> always equals 360 degrees, but lets prove this for a regular </span>octagon<span> (8-sides). First we must figure out what </span>each<span>of the interior </span>angles<span> equal. To do this we use the </span>formula<span>: ((n-2)*180)/n where n is the number of sides of the polygon</span>
10 different ways the awards can be rewarded.
Answer:
1
Step-by-step explanation:
The constant term in a perfect square trinomial with leading coefficient 1 is the square of half the coefficient of the linear term.
(2/2)² = 1
The missing constant term is 1.
Answer:
111°
Step-by-step explanation:
The two angles are alternate exterior angles, and those types of angles are always congruent if there are parallel lines.
Answer:
I think √170
Step-by-step explanation:
The points are A: (-3,5) and (4,-6) so we plug this into the distance formula
√(x2-x1)^2+(y2-y1)^2
√(4-(-3))^2+(-6-5)^2
√(7)^2+(-11)^2=
√49+121= √170 or a really long decimal which starts out 13.038404810
If I got the points wrong I can redo the problem and get another answer but I did the problem on my own and used a calculator and got the same answer
