Answer:
(2x-3) (2x+3)
zeros, x intercepts: -3/2, 3/2
Step-by-step explanation:
4x^2 -9
We know the difference of squares is a^2 -b^2
This factors into (a-b) (a+b)
Let 4x^2 =a^2
Taking the square root
2x =a
Let b^2 =9
Taking the square root
b= 3
(4x^2-9 ) = (2x-3) (2x+3)
To find the zeros, we set the equation equal to zero
(4x^2-9 ) = (2x-3) (2x+3) =0
Using the zero product property
2x-3 =0 and 2x+3 =0
2x-3+3 = 0+3 2x+3-3 = 0-3
2x=3 2x=-3
Divide by 2
2x/2 = 3/2 2x/2 = -3/2
x = 3/2 x = -3/2
These are the zeros of the equation (which are also the x intercepts)
Determine # of solutions using discrimination
D = b^2 - 4 ac
D=8^2 - 4 x 6 x ( -10 )
D = 304
D > 0
The quadratic equation has 2 real solutions
Answer:
Cousins Amber has: 6
(Let no. of cousins Amber has be represented as x)
Cousins Ashley has: 3x - 2
(3 X 6)- 2
18-2
16
Answer:
She will get $275.50 in return
Step-by-step explanation:
250 x 1.03 = 257.50