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dlinn [17]
3 years ago
6

Simplify the expression to a polynomial in standard form: (4x - 5)(2x^2 – 3x - 3)

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

8x³ - 22x² + 3x +15

Step-by-step explanation:

I do quick mathz

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What is ( 7v + 5 ) – ( 2v + 2 )
lara [203]

Answer:

5v+3. I hope I helped :'D

<u>Steps for answer!</u>

1. Remove parentheses.

7v+5-2v-2

2. Collect like terms.

(7v-2v)+(5-2)

3. Simplify.

5v+3

<u></u>

5 0
3 years ago
PLEASE HELP!!!!!<br> What is the equation of the line through (2,-5) and (6,3)
Vinvika [58]
We would have to use the formula y1 - y2 / x2 - x2.

-5 - 3 = -8 

2 - 6 = -4

Now we have -8/-4 and now we simplify to get 2/1 

sense the formula of a line is y= mx + b we now how the first part which is
y=2x+b

now we can plug in the plot from the original points to the equation to finsish the problem

3= 2 x 6 + b

6 divided by 2 is 3 and 3 times -3 is -9 so the final answer will be 

y=2x-9





8 0
3 years ago
Which has one solution:<br> 2x + 2y = 180<br> 0.1x + 7y = 78
Serhud [2]
Add all that up =189 / it
7 0
3 years ago
Please solve the equation
victus00 [196]

Answer:

1/5 + 9/5 x^2

None of the listed choices

Step-by-step explanation:

4x^2 +36       1

------------- * ----------

4x                 5x

Factor the numerator

4(x^2 +9)       1

------------- * ----------

4x                 5x

Cancel the 4

(x^2 +9)       1

------------- * ----------

x                 5x

Multiply

(x^2 +9)      

-----------------------

5x^2

We can break this into terms

x^2          9      

------   +  -----------------

5x^2       5x^2                

1/5 + 9/5 x^2

3 0
3 years ago
Read 2 more answers
Use a model to divide 2 ÷ 1/3
konstantin123 [22]

Answer:

the answer is 6

Step-by-step explanation:     since its a whole number u gotta put a 1 underneath to make it a im proper fraction so it would look like

2/1 ÷ 1/3   well then u gotta do KFC( keep it, change it, flip it) then it would look like this 2/1 x 3/1 you would get 6/1 which is 6 if u simplifly

3 0
3 years ago
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