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3 years ago

How many solutions are in 6-2(3-2x)=-4(3-x) ?

Mathematics

2 answers:

diamong [38]3 years ago

6 0

Answer:

There are no solutions.

Step-by-step explanation:

6-2(3-2x)=-4(3-x)

6 + -6 + 4x = -12 + 4x

4x = 4x - 12

-4 -4

0 = -12

Daniel [21]3 years ago

4 0

Answer:

Step-by-step explanation:

there is no solution:

6-2(3-2x) = -4(3-x)

6-6+4x= -12+4x

4x= -12+4x

0=-12

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Step-by-step explanation:

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3 years ago

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Answer:

4 drinks.

Step-by-step explanation:

-One drink is defined as having one-half ounce of pure ethyl alcohol; each of the following is considered "one drink." *1 oz of 100 proof distilled spirits at 50% alcohol.

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3 years ago

Express the perimeter of the triangle as a polynomial.

Tcecarenko [31]

The perimeter is just the sum of all of the side lengths.

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Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y

choli [55]

Answer:

The set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

Step-by-step explanation:

The augmented matrix of the system is $\left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right]$ .

We will use rows operations for find the echelon form of the matrix.

In row 2 we subtract $\frac{2}{3}$ from row 1. (R2- 2/3R1) and we obtain the matrix $\left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]$
We multiply the row 1 by $\frac{1}{3}$ .

Now we solve for the unknown variables:

$x_2+x_3=-7$ , $x_2=-7-x_3$
$x_1+2x_2+2x_3=-2$ , $x_1+2(-7-x_3)+2x_3=-2$ then $x_1=12$

The system has a free variable, the the system has infinite solutions and the set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

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