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solong [7]
3 years ago
12

Use the distributive property to factor the expression below. 544 y - 12 x 7

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0
The answer is 4 (136y-21)

Explanation:

Factor 4 out of 544y.
4 (136y) - 12*7

Factor 4 out of -12*7.
4 (136y) + 4 (-3*7)

Factor 4 out of 4.
(136y) + 4 (-3*7)
4 (136y- 3*7)

Multiply -3 by 7.
4 (136y - 21)
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What is 2×3(10)^-5 in standard form
Sindrei [870]
2×3(10)^{-5}=6×(10)^-5=\frac{6}{10^5} =0.00006
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4 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
Jade has a budget of $200
stealth61 [152]
And? It’s there a full question?
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3 years ago
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Andrej [43]
2 largest number is 1/3 and 4/13
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5 0
3 years ago
If f(x)=x^2 then evaluate (2+3i)
Virty [35]

Answer:

-5 + 12 i

Step-by-step explanation:

(2 + 3i)^2   = 4  + 6i  + 6i  + 9i^2

                 =   4   + 12 i   + 9(-1)

                     = - 5 + 12 i

3 0
2 years ago
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