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3 years ago

How can I find the area of this Trapezoid?

Mathematics

1 answer:

worty [1.4K]3 years ago

5 0

Trapezoid area = ((sum of the bases) ÷ 2) • height
It seems we'll have to count the lines in the graphic to get those lengths.
top base = 5
bottom base = 10
height = 6

Trapezoid area = (11 / 2) * 6
Trapezoid area = 5.5 * 6
Trapezoid area = 33

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A number z squared, decreased by 7

Vedmedyk [2.9K]

9514 1404 393

Answer:

z² -7

Step-by-step explanation:

A square is indicated using an exponent of 2. "Decreased by 7" means 7 is subtracted.

z squared, decreased by 7 is ...

z² - 7

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2 years ago

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

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3 years ago

The data set below has 6 values.

r-ruslan [8.4K]

Answer:

I belive the answer is 5

Step-by-step explanation:

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3 years ago