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Solnce55 [7]
3 years ago
6

PLS HELP ASAP I BEG YOU

Mathematics
2 answers:
fomenos3 years ago
8 0
56 IS THE ANSWER BYE NOW
Lana71 [14]3 years ago
3 0
56 what they said yeeeeeee
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If f(x) = 5x + 40, what is f(x) when x = -5?<br> оооо
mote1985 [20]
I think it’s 15..
cause you replace the x with -5 and solve the problem
8 0
3 years ago
Determine if the ordered pair is a solution of the equation. Is (0,0) a solution of y = x? options: True False
Monica [59]
I think false would be the answer
4 0
3 years ago
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Use the Distributive Property to solve the problem. [Example: 4(6+3) = 4(6)+4(3) = 24 + 12 = 36] 7(10 + 3)
riadik2000 [5.3K]

Answer:

91

Step-by-step explanation:

7(10+3)

7(10)+7(3)

70+21

91

5 0
3 years ago
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Someone please help marking brainliest
Luda [366]
Answer: (1, 4)


Explanation: When using the method of elimination, the goal is to eliminate a variable by either adding or subtracting the 2 equations. For this question, you can choose either to eliminate X or Y. I’ll eliminate X as an example:

In order to eliminate a variable, the same variable in both equations must have the same coefficient.

(1) 3x+y=7
(2) 2x+5y=22

Multiply (1) by 2:

(3) 6x+2y=14

Multiply (2) by 3:

(4) 6x+15y=66

Now that X in both equations has the same coefficient of 6, you can subtract the two equations to officially eliminate the variable and solve for Y:

Subtract (4) from (3):

-13y=-52
y=4

Now that you have the value of Y, substitute that into either one of the equations to get X. I’ll use the first equation as an example:

3x+(4)=7
3x=3
x=1

Therefore, the point of intersection is (1, 4).


Hope this helps シ

3 0
2 years ago
Which expression does not factor?<br><br> m3 + 1<br> m3 – 1<br><br> m2 + 1<br><br> m2 – 1
Luda [366]

Answer:

m^2 +1

Explanation:

All the other expressions can be factorized. Let's see why:

1) m^3 +1

This is the sum of the cubes, and this can be factorized as follows:

a^3+b^3=(a+b)(a^2-ab+b^2)

In this case, a=m and b=1, so we can factorize as

m^3+1=(m+1)(m^2-m+1)

2) m^3-1

This is the difference between two cubes, and this can be factorized as follows:

a^3-b^3=(a-b)(a^2+ab+b^2)

In this case, a=m and b=1, so we can factorize as

m^3-1=(m-1)(m^2+m+1)

3) m^2-1

This is the difference between two square numbers, and it can be factorized as follows

(a^2-b^2)=(a+b)(a-b)

In this case, a=m and b=1, so we can factorize as

m^2-1=(m+1)(m-1)

4 0
3 years ago
Read 2 more answers
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