Answer:
Option D
Step-by-step explanation:
32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).
Distance between two points
and
is given by the expression,
Distance = 
Distance between M(2, -3) and N(3, 1) will be,
MN = 
= 
= 
Distance between M(2, -3) and O(-3, 1),
MO = 
= 
= 
Distance between N(3, 1) and O(-3, 1),
NO = 
= 6
Condition for right triangle,
c² = a² + b² [Here c is the longest side of the triangle]
By this property,
MO² = MN² + NO²

41 = 17 + 36
41 = 51
False.
Therefore, given triangle is not a right triangle.
Since, length of all sides are not equal, given triangle will be a scalene triangle.
Option D is the correct option.