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Strike441 [17]
3 years ago
10

A tortilla measures 8 inches in diameter what is your tortillas area

Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

a=50.27 inches squared

Step-by-step explanation:

Radius:

r=d/2

r=8/2

r=4

Area:

a=\pi r^{2}

a=\pi (4^{2})

a=\pi (16)

a=50.27  inches^{2}

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Makayla leans a 18-foot ladder against a wall so that it forms an angle of 64 degrees with the ground. What’s the horizontal dis
aleksandr82 [10.1K]

The ladder and the outside wall form a right triangle

The distance from the base of the ladder is 7.89 feet

<h3>How to determine the distance to the base of the ladder?</h3>

The given parameters are:

Length (L) = 18 feet

Angle of elevation (θ) = 64 degrees

The distance (D) from the base of the ladder is calculated using the following cosine ratio

cos(θ) = D/L

So, we have:

cos(64) = D/18

Make L the subject

D = 18 * cos(64)

Evaluate the product

D = 7.89

Hence, the distance from the base of the ladder is 7.89 feet

Read more about right triangles at:

brainly.com/question/2437195

8 0
2 years ago
Determine which pizza is the better buy in each situation. The 10-inch diameter pizza for $8.99 or the 6-inch diameter pizza for
Papessa [141]
You could see the fraction of each, so 10/8.99 would be 1.11. and 6/5 which would be 1.2, so the 6 inch costs more, so the 10 inch is better
6 0
3 years ago
Read 2 more answers
2. Sum of two numbers = 16
topjm [15]
The numbers are 11 and 5
There product is 55
6 0
3 years ago
Read 2 more answers
Solve the problems.<br><br> 100 POINTS<br> BRAINLIEST IF UR RIGHT
lora16 [44]

ACD by AAS.

We're given m1 = m2, ADC = ADB, and both triangles share AD, so it must be AAS.

ABD by SAS.

We're given AB = AE and AC = AD, but the middle part is a mystery. We're not given BD and CE/ADB and ACE so it's pretty hard to know. Could be SAS or SSS. If you have either BD and CE, it's SSS. If you have ADB and ACE, it's SAS.

Took Geometry 4 years ago so I'm a bit iffy on the second. Forgive me D:

3 0
3 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
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