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mariarad [96]
3 years ago
7

-30=5(x+1) x=? Solve for X

Mathematics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

=-7

Step-by-step explanation:

-30=5(x+1)

-30=5x+5

-35=5x

= -7

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For tax purposes, a car rental company assumes each car in their fleet depreciates by 6% per year. If the initial value of a car
n200080 [17]

The value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent \rm y = a^x

where a is a constant and a>1

We can solve this problem by exponential function:

The word  depreciate means the price is decreasing.

We can find the value be when the car is 10 years old:

p = 38800(1 - 0.06)¹⁰

p = 38800(0.94)¹⁰

p = 20898.266 ≈ $20898.27

Thus, the value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.

Learn more about the exponential function here:

brainly.com/question/11487261

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6 0
1 year ago
Please help!! This is so confusing! 100 points!!
masya89 [10]

Answer:

The value of the expression given is:

  • 4

Step-by-step explanation:

First, you must divide the expression in three, and to the final, you can multiply it:

  1. [(3^8)*(2^(-5))*(9^0)]^(-2)
  2. [(2^(-2))/(3^3)]^4
  3. 3^28

Now, we can solve each part one by one:

<em>First part. </em>

  • 3^8 = 6561
  • 2^(-5) = 0.03125
  • 9^0 = 1 (Whatever number elevated to 0, its value is 1)
  • (6561 * 0,03125 * 1) = 205.03125

And we elevate this to -2:

  • 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688 </u>

<em>Second part. </em>

  • 2^(-2) = 0.25
  • 3^3 = 27
  • 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925

And we elevate this to 4:

  • 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528 </u>

<em>Third Part. </em>

  • 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>

At last, we multiply all the results obtained:

  • 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>

<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.

3 0
3 years ago
Read 2 more answers
Find the sum of 10 x 2 + 7 x + 6 10x 2 +7x+6 and 6 x + 5 6x+5.
dusya [7]

The sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11

<h3>Sum of expressions</h3>

Expressions are equations separated by mathematical signs. This expressions are known to contains certain unknowns

Given the following expression

10x^2 +7x+6 and 6x + 5

We are to take the sum of both expression to have:

f(x) = 10x^2 +7x+6 + 6x + 5

Collect the like terms

f(x) = 10x^2 + 7x + 6x + 6 + 5

f(x) = 10x^2 + 13x + 11

Hence the sum of the given expression expressed as a quadratic equation is 10x^2 + 13x + 11

Learn more on sum of functions here: brainly.com/question/11602229

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8 0
1 year ago
HELP ME PLEASE I NEED THIS LOVE U GUYS &lt;33
Sedaia [141]

Answer:

\huge\boxed{\sf Volume = 384 \ cm^3}

Step-by-step explanation:

Slant Height = 10 cm

Base Edge = 12 cm

<u>Finding the Height using Pythagorean Theorem:</u>

\sf c^2 = a^2 + b^2 \\\\Where \ c = 10\ cm , b = 6\ cm [Half of 12] \ and \ a \ is \ height\\\\10^2 = a^2 + 6^2\\\\100=a^2 +36\\\\100-36 = a^2\\\\64 = a^2\\\\Taking \ sqrt \ on \ both \ sides\\\\Height= 8 \ cm

\rule[225]{225}{2}

<u>Now, Finding the volume:</u>

\sf Volume = a^2 \frac{h}{3}\\\\ Where \ a \ is base \ edge \ and \ h \ is \ height\\\\Volume = (12)^2 \frac{8}{3} \\\\Volume = 144 \frac{8}{3} \\\\Volume = 48*8\\\\\bold{Volume = 384 \ c m^3}

\rule[225]{225}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
8 0
3 years ago
A submersible traveling at a depth of 250 feet dives at an angle of 15 degrees with respect to a
kipiarov [429]

Answer:

\boxed{\text{652 ft}}

Step-by-step explanation:

The submersible is diving at a down angle of 15° along the hypotenuse AC of triangle ABC.  

Its horizontal track along the surface AB is 1500 ft.

\begin{array}{rcl}\tan A & = &\dfrac{BC}{AC}\\\\\tan 15^{\circ} & = & \dfrac{a}{1500}\\\\0.2679 & = & \dfrac{a}{1500}\\\\a & = & 1500 \times 0.2679\\& = & \textbf{402 ft}\\\end{array}

The submersible was already at a depth of 250 feet when it began the dive.

New depth = 250 + 402 = 652 ft

\text{The depth after the dive is }\boxed{\textbf{652 ft}}

6 0
3 years ago
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