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2 years ago

5

Someone pls help me, i’ll mark brainlist

1 answer:

Over [174]2 years ago

6 0

Answer:

Function H h(t) = -6.1 + 19t - 55

Step-by-step explanation:

Let t = 1

<u>Function F</u>

h(t) = 6.1t^2 + 19t - 54.4

h(1) = 6.1(1)^2 + 19(1) - 54.4

h(1) = 6.1 + 19 - 54.4

h(1) = -29.3

<u>Function G</u>

h(t) = -24.1t^2 + 2.8

h(1) = -24.1(1)^2 + 2.8

h(1) = -24.1 + 2.8

h(1) = -21.3

<u>Function H</u>

h(t) = -6.1t^2 + 19t - 55

h(1) = -6.1(1)^2 + 19(1) - 55

h(1) = -6.1 + 19 - 55

h(1) = -42.1

<u>Function J</u>

h(t) = -6.1t^2 + 19t + 0.99

h(t) = -6.1(1)^2 + 19(1) + 0.99

h(t) = -6.1 + 19 + 0.99

h(t) = 13.89

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Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

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3 years ago

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FromTheMoon [43]

Answer:

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