Ask question

Ask question

All categories

2 years ago

7

A tv that normally cost $800

1 answer:

sukhopar [10]2 years ago

6 0

what is the question it might be an Sony-75"

You might be interested in

Solve the system by substitution 10x-2y=-16 and y=3x

lesantik [10]

The answer would be x=-4.

5 0

2 years ago

The quotient of a number and three, increased by one <br><br><br> Using the variable N

solniwko [45]

N÷3+1 or can be stated as 3÷n+1

5 0

2 years ago

For the function f(x)=3xsquared- 2x+5 find f(1) f(-2) and f(a)

Oksanka [162]

$f(x)=3x^2-2x+5\\\\
f(1):\ \ Substitude\ 1 \ as\ x\ into\ function:\\
f(1)=3*1^2-2*1+5=3-2+5=\textbf{6}\\\\
f(-2)\ \ Substitude\ x=-2\\
f(-2)=3*(-2)^2-2*(-2)+5=3*4+4+5=12+4+5=\textbf{21}\\\\
f(a)\ \ substitude\ x=a\\
f(a)=\underline{3a^2-2a+5}$

4 0

3 years ago

If (-3) exponent -5 = 1/x, what is the value of x? <br> -243<br> - 1/243<br> 1/243<br> 243

trapecia [35]

Answer:

$\boxed {-243}\\$

Step-by-step explanation:

$\begin{array}{rclr}(-3)^{-5} & = & \dfrac{1}{x}& &\\(-3)^{5} & = & x &\text{Inverted each side of the equation}\\x & = & \boxed {\textbf{{-243}}}\\\end{array}$

6 0

2 years ago

Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I

fredd [130]

Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

<em>Axis of symmetry:</em>

<em> $x =4$ </em>

Step-by-step explanation:

<u>First factorize the function</u>

$f (x) = -2x ^ 2 + 16x-30$

<em>Take -2 as a common factor.</em>

$-2(x ^ 2 -8x +15)$

<em>Now factor the expression $x ^ 2 -8x +15$ </em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

$f (x) = -2(x-5)(x-3)$

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form $ax ^ 2 + bx + c$ the x coordinate of its vertex is:

$x = \frac{-b}{2a}$

In the function $f (x) = -2x ^ 2 + 16x-30$

$a = -2\\b = 16\\c = 30$

<u>Then the vertice is:</u>

$x = \frac{-16}{2(-2)}\\\\x = 4$

The y coordinate of the symmetry axis is

$y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2$

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

$x = 4$

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

6 0

2 years ago