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Juli2301 [7.4K]
3 years ago
13

4. Ten outcomes are all equally likely from an event and you choose one of them at random. What is the probability that the outc

ome you chose will be the outcome of the event?
0.50
0.10
0
0.90
Mathematics
2 answers:
Maksim231197 [3]3 years ago
7 0
1/10 because there are ten outcomes
photoshop1234 [79]3 years ago
6 0

Answer:  The correct option is (B) 0.10.

Step-by-step explanation:  Given that ten outcomes are all equally likely from an event and we choose one of them at random.

We are to find the probability that the outcome we chose will be the outcome of the event.

Since the outcomes are equally likely, so

let A denotes the event that any one of the outcome is chosen and S be the sample space for the experiment.

Then, n(A) = 1 and n(S) = 10.

Therefore, the probability  that the outcome we chose will be the outcome of the event is given by

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{1}{10}=0.10.

Thus, teh required probability is 0.10.

Option (B) is CORRECT.

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At a store, apples cost $0.80 $0.80 each and oranges cost $0.95 $0.95 each. Harry buys some apples and oranges and spends $9.55
gregori [183]

Answer:

Harry buys 6 apples and 5 oranges at the store.

Step-by-step explanation:

Given:

Cost of each apples = $0.8

Cost of each oranges = $0.95

Total money spend =$9.55

Number of fruits bought= 11

We need to find the number of apples bought and number of oranges were bought.

Solution:

Let the number of apples bought be 'a'.

Let the number of oranges were bought be 'o'.

Number of fruits bought= 11

So we can say that;

Number of fruits bought is equal to sum number of apples bought and number of oranges were bought.

framing in equation form we get;

a+o=11 ⇒ equation 1

Now we can say that;

Total money spend is equal to number of apples bought multiplied by Cost of each apples plus number of oranges were bought multiplied by Cost of each oranges.

framing in equation form we get;

0.8a+0.95o=9.55 ⇒ equation 2

Now Multiplying equation 1 by 0.8 we get;

0.8(a+o)=0.8\times11

0.8a+0.8o=8.8 ⇒ equation 3

Subtracting equation 3 from equation 2 we get;

0.8a+0.95o-(0.8a+0.8o)=9.55-8.8\\\\0.8a+0.95o-0.8a-0.8o=0.75\\\\0.15o=0.75

Dividing both side by 0.15 we get;

\frac{0.15o}{0.15}=\frac{0.75}{0.15}\\\\o=5

Substituting the value of o in equation 1 we get;

a+o=11\\\\a+5=11\\\\a=11-5=6

Hence Harry buys 6 apples and 5 oranges at the store.

3 0
3 years ago
For a circle with a diameter of 6 meters, what is the measurement of a central angle (in degrees) subtended by an arc with a len
Sholpan [36]

Answer:

\boxed{\boxed{\theta=150^{\circ}}}

Step-by-step explanation:

We know that,

\text{Arc length}=r\cdot \theta

where,

r = radius,

θ = central angle in radian.

Given,

diameter = 6 m, so radius = 3 m.

\text{Arc length}=\dfrac{5}{2}\pi

Putting the values,

\Rightarrow \dfrac{5}{2}\pi=3\theta

\Rightarrow \theta=\dfrac{5}{2\times 3}\pi

\Rightarrow \theta=\dfrac{5}{6}\pi=\dfrac{5}{6}\times 180^{\circ}=150^{\circ}


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3 years ago
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Please hurry<br> What function is represented in the table?
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Answer:

B. 3(2^x)

Step-by-step explanation:

3(2^x) is the only function that yielded the given outputs when the inputs were plugged in.

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