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Juli2301 [7.4K]

3 years ago

13

4. Ten outcomes are all equally likely from an event and you choose one of them at random. What is the probability that the outc

ome you chose will be the outcome of the event?
0.50
0.10
0
0.90

2 answers:

Maksim231197 [3]3 years ago

7 0

1/10 because there are ten outcomes

photoshop1234 [79]3 years ago

6 0

Answer: The correct option is (B) 0.10.

Step-by-step explanation: Given that ten outcomes are all equally likely from an event and we choose one of them at random.

We are to find the probability that the outcome we chose will be the outcome of the event.

Since the outcomes are equally likely, so

let A denotes the event that any one of the outcome is chosen and S be the sample space for the experiment.

Then, n(A) = 1 and n(S) = 10.

Therefore, the probability that the outcome we chose will be the outcome of the event is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{1}{10}=0.10.$

Thus, teh required probability is 0.10.

Option (B) is CORRECT.

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At a refinery, there are two loading docks. The first dock is for ships with a capacity of more than 300,000 gallons. The second

mart [117]

Ship 3 is the only one with less than 300,000 gallons capacity,

ship 1 has a capacity of that given value, and so does ship 2

7 0

4 years ago

Point A is located at (4, 0) and is reflected in the x-axis. What are the coordinates of point A'?

Deffense [45]

Answer:

The point (4,3) reflected about the x axis,

=> The x remains the same, the y flips over the x axis to be negative

(4,3) ==>> (4,-3)

The point (-3,-8) is reflected in the y-axis.

=> The y remains the same, the x flips over the y axis to be negative

(-3,-8)==>>(3,-8)

The point (2,4) is reflected in the line x = -3.

=> The x remains the same, the y flips over the x= -3 line.

Instead of reflecting over the x axis (or the x = 0) line

and just being +4 or 4 above the x axis to -4 or 4 below the x axis

you have +4 being 7 above the x= -3 line so you need

7 below the x= -3 line or -10 SO

(2,4)==>>(2,-10)

The point (a, b) is reflected in the line y = x

Consider that the line x=y is a 45 degree diagonal.

Imagine a point on the x axis at +3 i.e. (3,0)

Imagine a line perpendicular to x=y from the point (3,0)

(sorry there is no way to draw on here - try drawing it)

The line would hit the y axis at (0,3)

So you can see the x becomes y and y becomes x.

(a,b)==>>(b,a)

For

ΔXYZ is defined by its vertices X(1,3), Y(-3,5), and Z(0, -5).

ΔXYZ is reflected in the y-axis.

So for each of of the 3 points X, Y, and Z reflect them about

the y axis the same way in the second example above

and you will have the 3 new points X’, Y', and Z’

The translation T: (x, y) → (x -2, y + 4) maps the point (2, -3) to

The translation T: (x, y) → (x + 3, y - 2) maps the point (-4, -3) to

What you need to do here is just plug the values for X and Y into the translation.

e.g. for T: (x, y) → (x -2, y + 4) plug (2,-3) of x=2 y=-3 into (x -2, y + 4) and get the new values.

Step-by-step explanation:

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5 0

4 years ago

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

3 years ago

Please help! I'll mark as brainliest

Rudik [331]

Answer:

your work is not clearly taking sorry i can't see

7 0

3 years ago

1/3+5/8..................

mr Goodwill [35]

Answer:

23/24 is the answer

8 0

3 years ago