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Andru [333]
3 years ago
6

Benji and Joel are raising money for their class trip by selling gift wrapping paper. Benji raises $15 by selling 4 rolls of red

wrapping paper and 4 rolls of foil wrapping paper. Joel raises $15 by selling 8 rolls of red wrapping paper and 2 rolls of foil wrapping paper. For how much are Benji and Joel selling each roll of red wrapping paper?
Mathematics
1 answer:
Ahat [919]3 years ago
4 0
The price for red paper = 1.25
the price for foil = 2.5
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The sum of 2 numbers is 65 and the difference is 7
Dahasolnce [82]

Answer:

Hello There!!

Step-by-step explanation:

The answer is=>The sum is x + y = 65

The difference is x - y = 7 .....x = 7 + y

7 + y + y = 65

7 + 2y = 65

2y = 58

y = 29

x + y = 65

x + 29 = 65

X = 36

The Sum: 36 + 29 = 65

The Difference: 36 - 29 = 7

hope this helps,have a great day!!

~Pinky~

3 0
3 years ago
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Can someone help me to answer this PLEASE!!!!!
Anastasy [175]

Move the decimal point 6 places to the right to get the answer. the answer would be    

6039000.000

in decimal notation, it should be 6/1 x 1000000/1000000 + 0/1 x 100000/10000 + 3/1 x 10000/10000 + 9/1 x 1000 + 0/1 x 100/100 + 0/1 x 10/10 + 0/1 x 1/1

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Dafna11 [192]

Answer:

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3 0
4 years ago
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So 29 is a monomial also​
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Answer:

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Step-by-step explanation:

8 0
3 years ago
What is the following quotient 6-3(^3√6)/^3√9
azamat

Answer:

2\sqrt[3]{3}-\sqrt[3]{18}

Step-by-step explanation:

We first rationalize the denominator.  This means we multiply the numerator and denominator by a factor that will make the denominator a whole number.

Our denominator is \sqrt[3]{9}; this can also be written as 9^{\frac{1}{3}}.

For 9 to be a whole number, its exponent must be a whole number.  We want to add 2/3 to the exponent of 9 on the bottom; this means we multiply by 9^{\frac{2}{3}}:

On the numerator, this gives us:

6(9^(2/3))-3(6^(1/3))(9^(2/3))

= 6\sqrt[3]{9(9)} -3\sqrt[3]{2(3)}(\sqrt[3]{9(9)})  \\\\=6\sqrt[3]{3(3)(3)(3)}-3\sqrt[3]{2(3)(3)(3)(3)(3)}\\\\=6(3)\sqrt[3]{3}-3(3)\sqrt[3]{2(3)(3)}\\\\=18\sqrt[3]{3}-9\sqrt[3]{18}

On the denominator, we will have:

(9^(1/3))(9^(2/3)) = 9^(3/3) = 9^1 = 9

This gives us:

\frac{18\sqrt[3]{3}-9\sqrt[3]{18}}{9}\\\\=2\sqrt[3]{3}-\sqrt[3]{18}

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3 years ago
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