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krek1111 [17]
3 years ago
11

Assume time t runs from zero to 2π and that the unit circle has been labled as a clock. Match each of the pairs of parametric eq

uations with the best description of the curve from the following list. Enter the appropriate letter (A, B, C, D, E, F ) in each blank. A. Starts at 12 o'clock and moves clockwise one time around. B. Starts at 6 o'clock and moves clockwise one time around. C. Starts at 3 o'clock and moves clockwise one time around. D. Starts at 9 o'clock and moves counterclockwise one time around. E. Starts at 3 o'clock and moves counterclockwise two times around. F. Starts at 3 o'clock and moves counterclockwise to 9 o'clock. 1. x=cos(2t); y=sin(2t) 2. x=sin(t); y=cos(t) 3. x=cos(t); y=−sin(t) 4. x=−sin(t); y=−cos(t) 5. x=−cos(t); y=−sin(t)

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
8 0

Answer:

1 = D

2= B

3 = C

4 = A

5 = F

Step-by-step explanation:

CHECK ATTACHMENT FOR EXPLANATION

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What is meaning of rate?
Alja [10]

Answer:

1.a measure, quantity, or frequency, typically one measured against another quantity or measure.

Step-by-step explanation:

2.a fixed price paid or charged for something.

4 0
3 years ago
Read 2 more answers
Type the correct answer in the box.
Pepsi [2]

Answer:

f(g(-64)) = -190

Step-by-step explanation:

The functions are not well written.

Let us assume;

f(x) = x+1

g(x) = 3x+1

f(g(x)) = f(3x+1)

Replace x with 3x+1 in f(x)

f(g(x)) = (3x+1) + 1

f(g(x)) = 3x + 2

f(g(-64)) = 3(-64) + 2

f(g(-64)) = -192+2

f(g(-64)) = -190

<em>Note that the functions are assumed but same method can be employed when calculating composite functions</em>

8 0
2 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

3 0
2 years ago
Two cards are drawn from a deck of 52 playing cards. The first card is replaced into the deck before the 2nd card is drawn. What
Firlakuza [10]

Answer:

1/676

Step-by-step explanation:

There are 52 cards

P(Ace of spades) = Number of aces of spades / total = 1/ 52

The replace the card

There are 52 cards

There are 4 kings

P(king) = number of kings / total = 4/52 = 1/13

P( ace of spades , replace, any king) = 1/52 * 1/13 = 1 /676

5 0
3 years ago
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