We know that the perimeter of a rectangle is twice the length, plus twice the width.
P = 2L + 2W
We also know that the perimeter is 156.
P = 156
Finally, we know that the width is 12 less than the length.
W = L - 12.
The next thing that we do is substitute the information that we have into the original equation:
P = 2L + 2W
156 = 2L + 2(L - 12)
From this point we start to solve
156 = 2L + 2L - 24 <---we multiplied the '2' through the parenthesis
156 + 24 = 2L + 2L - 24 + 24
180 = 2L + 2L <--- getting like terms on same sides
180 = 4L <---combining like terms
180/4 = 4L/4 <--- getting like terms on same sides
45 = L <---now we have a value for L
Now we take the known value for L and substitute it in to our equation for W
W = L - 12
W = 45 - 12
W = 33
So now we have Length = 45 and Width = 33.
Answer:
y=27 when x=2
Step-by-step explanation:
y varies inversely as the cube of x
y=k(1/X^3)
y=1 when x=6
y=k(1/X^3)
1=k(1/6^3)
1=k(1/216)
k=1÷1/216
K=1×216/1
k=216
find y when x=2
y=k(1/X^3)
y=216(1/2^3)
y=216(1/8)
y=216/8
y=27
Answer:
3rd integer:n+2
Step-by-step explanation:
