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Alinara [238K]
3 years ago
8

The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

create triangle A'B'C', which set of coordinates represents the vertices of triangle ABC?
​
Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

A' =  (1,2)

B'=(2,1)

C' =(3,3)

Step-by-step explanation:

Given

A = (3,6)

B = (6,3)

C = (9,9)

Scale = \frac{1}{3}

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

A = (3,6)   B = (6,3)   C = (9,9)

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

(A'B'C') = Scale\ Factor * (ABC)

A' = \frac{1}{3} * A

A' = \frac{1}{3} * (3,6)

A' =  (\frac{3}{3},\frac{6}{3})

A' =  (1,2)

B' = \frac{1}{3} * B

B' = \frac{1}{3} * (6,3)

B' = (\frac{6}{3},\frac{3}{3})

B'=(2,1)

C' = \frac{1}{3} * C

C' = \frac{1}{3} * (9,9)

C' = (\frac{9}{3},\frac{9}{3})

C' =(3,3)

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Step-by-step explanation:

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solution

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