Question

Translate the statements into a confidence interval for p. Approximate the level of confidence. In a survey of 8451 U.S. adults, 31.4% said they were taking vitamin E as a supplement. The survey's margin of error is plus or minus 1%.

Answer 1

Answer:

The  confidence interval is  $0.304 < p < 0.324$

Step-by-step explanation:

From the question we are told

      The sample proportion $\r p = 0.314$

      The margin of error  is $E = 0.01$

The confidence interval for  p is mathematically represented as

       $\r p - E < p < \r p + E$

=>    $0.314 - 0.01 < p < 0.314 + 0.01$

=>   $0.304 < p < 0.324$